TITANOSARUS !!!!!!!!!!!27 Jun 2023 12:44
Ok so had a stab at the numbers for MA1/TGB6 , credit to Keithoz for the formula
shallow gas
Uniform thickness of 15m (it may be thicker or thinner)
* Area 58km² = 58,000,000m²
* Porosity 20% (likely to be better consolidated than MOU turbidites, so lower than the 25% assumed for them)
* 66% recoverability (imo on the low side, but this is what is assumed in the CPR & by FDC)
* 70% charge (CPR again)
* 75% attributable to PRD
* Gas expansion Factor of 86. Rule of thumb is lithostatic pressure is 1 psi for each 1ft of depth. 950m x 3.28 = 3116ft depth, plus 122psi overpressure = 1270psi. 1 Bar = 14.7psi. 1270/14.7 = 220Bar.
So, 15 x 58,000,000 x 0.2 x 0.66 x 0.7 x 0.75 x 220 = 13264020000 m³
1m³ = 35.3ft³ - near enough 376 BCF net to PRD
Adjust the assumptions to come up with your own numbers.
...........
RNS today
"In particular the Ma Sand potential has been enhanced over a wider area with the possibility of a larger gas trap being effectively sealed covering up to 58km². The shallow gas potential of MOU-3 has exceeded all pre-drill expectations."
pre drill - target was 320BCF P50
CNG $4.84 per BCF
376bcf x $4.84 = $1820m x 0.8 =
£1456m
...............
MOU FAN
MOU-3 (June 2023) will appraise MOU 1 gas find, to firm up thicker sands, CONTINGENT 295BCF P50 based on 19m sands in MOU fan
295 x $4.84 = $1427.80 x 0.8 =
£1142m
................
total
£1456 + £1142m =
£2598m
*43m Confirmed today, exceeding P50 19m , P10 ? further upside ..
.............
MOU 4
Appraise MOU fan but also test "BLUE SKY" potential
TITANOSAURUS !!!!!!!!!!!!!!!
Area 126km² = 126,000,000m²
* Porosity 20% (likely to be better consolidated than MOU turbidites, so lower than the 25% assumed for them)
* 66% recoverability (imo on the low side, but this is what is assumed in the CPR & by FDC)
* 70% charge (CPR again)
* 75% attributable to PRD
* Gas expansion Factor of 86. Rule of thumb is lithostatic pressure is 1 psi for each 1ft of depth. 1500m x 3.28 = 4920ft depth, plus 122psi overpressure = 5042psi. 1 Bar = 14.7psi. 5042/14.7 = 343Bar.
So, 200 x 0.5 x 126,000,000 x 0.2 x 0.66 x 0.7 x 0.75 x 343 = 299,500,740,000 m³
1m³ = 35.3ft³ -
8.4 TCF net to PRD
Adjust the assumptions to come up with your own numbers
...............
*200m reservoir, not sure on the net to gross expectation assume 50%, so 100m used for the calculation..
Will PRD put a bit of meat on the bone in the potential numbers on RNS spud ??
Seems a bit of cat and mouse at play