RE: Morning All15 Jan 2021 13:32
Hi Mickey
You had asked me for some estimation on LABOLA.......which I now detail :
****Based on the previous drilling however, an Exploration Target of 15-30Mt grading between 1 and 1.5g/t Au (0.5 to 1.5Moz gold) is interpreted. The area has previously been extensively drilled by two companies, Taurus Gold and High River Gold, who each held separate parts of the area with some overlap. All up, over 65,000m drilling has been conducted on the project as shown on the table and image below. " THE AREAS OF ARTISINAL MINING SUB-PARALLEL TO THE THREE MAIN ZONES SUGGESTS SIGNIFICANT ADDITIONAL EXPLORATION POTENTIAL EXISTS OUTSIDE THESE ZONES AND NOT COVERED BY PREVIOUS DRILLING ". *******
Please feel free to correct me on the undermentioned parameters / assumptions that I have used in my calculations and if required, I will re-calculate the workings:
PARAMETERS (AND ASSUMPTIONS) USED ARE AS FOLLOWS:
a) Strike length = 9km (=9000m)
b) Width = taken average across the strike length = 0.3km (=300m)
c) Depth = taken average across the strike length = 0.1km (=100m)
d) Density for the area = assumed industry average in west Africa = 2.4 Tonnes /meter cube
e) You will note later in the calculation that I will aim to take ONLY 1/10 th of estimated resource figure to take account of the fact that even though some holes may have returned say over 100 g/Tn, these COULD BE isolated ones or indeed the width of the depth in some areas may not be the same as assumed throughout the strike length of 9km. I have even gone further to reduce the strike length of 9km TO ONLY 1/10 th on the assumption IF the strike length was NOT CONTINUOUS ( IT MAY BE THE CASE THAT THE WHOLE OF THE STRIKE LENGTH IS CONTINUOUS and I therefore do not need to reduce 9km to 1/10th)
(f) Based on the company data I have taken 1 g/T grading
(g) Recovery rate of gold = 80%
So, here it is:
(1) 9km x 0.3km x 0.1km x Density
(2) = 9000m x 300m x 100m x (2.4 Tonne/meter cube)
(3) = 270,000,000 meter cube x 2.4 Tonne/ meter cube
(4) = 648,000,000 Tonnes
(5) Resource in grams = 648,000,000 T x 1 grams /T = 648,000,000 grams
(6) Resource in ounces - 648,000,000 grams / 34.2857 = 18,900,000ounces DIVIDE BY FACTOR 10 = 1,890,000 ounces
(7) Recovery rate of gold (say 80%) x 1,890,000 ounces = 1,500,000 ounces
(8) ********This would be similar to GGP's share of their recent find.*********
(9) If this turns out to be the case then at 1.5m ounces, the impact on PAT share price can be very significant. AND, IF ARTISINAL MINING SUB-PARALLEL TO THE THREE MAIN ZONES SUGGESTS SIGNIFICANT ADDITIONAL EXPLORATION POTENTIAL EXISTS OUTSIDE THESE ZONES AND NOT COVERED BY PREVIOUS DRILLING then there is potential to increase the resource as the company has suggested.