RE: Re - Newcest6 Dec 2019 12:00
Ok so if we assume the parameters as Timid suggested (conservative some may say) earlier
300m diameter & 1000m depth.
Volume = pi*r²*d (3.1416*150²*1000) = 70,686,000 m³
Tonnes = Volume * Relative Gravity (70,686,000*2.7) = 190,852,200 tonnes
Assume (conservative) 1.5g/t (190,852,200*1.5) = 286,278,300 g
Troy Ounce = g/31.1 (286,278,300/31.1) = 9,205,090oz
The thing here is if we have a base resource of somewhere around this – now for every 100m that we extend (assuming the width stays at 300m) the formula changes to.
Volume = pi*A*B*d (where A & B are the radius of the two axis)
So, for 400m of strike length assuming the depth stayed consistent the numbers would be.
Volume = pi*A*B*d (3.1416*150*200*1000) = 94,247,700 m³
Tonnes = Volume * Relative Gravity (94,247,700*2.7) = 254,468,790 tonnes
Assume (conservative) 1.5g/t (254,468,790*1.5) = 381,703,185 g
Troy Ounce = g/31.1 (381,703,185/31.1) = 12,272,033 oz
So, for every extra 100m of strike (assuming constant width & depth) the orebody could grow by 3 million ounces.
If you change the g/t to 2 then the initial figure is 12.2 million and it grows by 4 million for every 100m
Obviously, this is just for illustration and is not to be taken as gospel – it just gives an idea of where we could be at and how quickly this could grow.